| | "I was finishing a backgammon game and had two pieces left, one on 4, and the other on 2. I rolled a 6, 3, and I imagined the backgammon game was above, but my opponent stated that I had to move my 4 piece to the 1 slot, then consider the two off with the six roll. She stated I had to do this simply because I had the chance to move my piece, it's a backgammon rule! I've got $. riding on this, is it correct? What is the right backgammon rule? Please respond!"
We have acquired several messages as the above a single and determined to supply a useful formula for novices. The formula is really straightforward:
"If the quantity of the dice that you have rolled is equal or larger than the amount of the row* that your checker** is located you bear off. If the dice number is smaller sized than the row quantity you must perform that number by moving your checker towards rows with smaller quantity."
Row*: the space, the slot, the area. that you perform or spot your checkers. 24 rows exist on the backgammon board.
Checker**: the stone, the piece. that you play on the board. Each player has 15 checkers.
The formula might seem difficult but do not worry, it's not, allow me describe! To begin to bear off you ought to enter all your checkers into your house location and in your house location you have six rows. Let us put a number to each of these six rows. The initial 1 is "r1" which is also the row that your opponent's two checkers are positioned on the beginning of the game.
Then you have "r2", "r3", "r4", "r5" lined side by side and the last 1 is "r6" in which you spot 5 checkers on the beginning. Now you know that the row amount is a quantity in between one and 6. Same of the dice quantity!
Now suppose that you have a single checker in row five and a single checker in row two (far better is to use your real backgammon board and simulate these choices), and you have rolled a "six + three", 6 is larger than 5 and 3 is larger than 2, and you bear off your two checkers!
Suppose you have two checkers in "r4" and one checker in "r1", you have rolled a "4 + three", you bear off one checker from "r4" with your dice quantity four, and for dice number 3 you must move 1 checker from "r4" to "r1".
You have three checkers in "r6" and 2 checkers in "r3", four checkers in "r2" and 3 checkers in "r1". You have rolled a "five + four". Result Hk 6d Tercepat Sadly you will move two checkers from "r6" to "r2" and "r1", and you can not bear any checker off.
You have three checkers in "r6", 3 in "r5", two in "r4", four in "r2" and 3 in "r1", and you have rolled a "double3", simply because your "r3" is empty you need to move two checkers from "r6" to "r3" and bear two checkers off from "r3".
You have 3 checkers in "r3", 4 checkers in "r2" and five checkers in "r1", you have rolled a "five + four". You will bear 2 checkers off from "r3".
You have two checkers in "r6", four checkers in "r5", 1 checker in "r4", 3 checkers in "r3", three checkers in "r2" and two checkers in "r1". You have rolled a "double4". You will bear one checker off from "r4", move two checkers from "r6" to "r2" and one checker from "r5" to "r1". Only 1 checker has been born off.
Maybe the worst position is when you have only two checkers remaining in "r2" and you roll 1 "1", for illustration a "three + one". Although three is greater than "r2", 1 is smaller sized, and you will bear a single checker off but move the final one to "r1" and wait for the subsequent hand. Same for "two + 1" or "4 + 1" | | | |
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